x^2(x-3)+12-4x=0

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Solution for x^2(x-3)+12-4x=0 equation: 


Simplifying
x2(x + -3) + 12 + -4x = 0

Reorder the terms:
x2(-3 + x) + 12 + -4x = 0
(-3 * x2 + x * x2) + 12 + -4x = 0
(-3x2 + x3) + 12 + -4x = 0

Reorder the terms:
12 + -4x + -3x2 + x3 = 0

Solving
12 + -4x + -3x2 + x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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